Hi Rob. You use 2.6oz of this into 1 gallon of gas for a 50:1 ratio. Thanks for asking. Greg
Hi Irish. A 50:1 ratio is 2.6oz to 1 gallon of gas. Thanks for asking. Greg
Hi Charles, Yes this is a 50:1 mix. You will need to have 2.5 gal of gas and pour the complete bottle into the gas. Hope this helps. Greg
The ratio in question is the number of parts gasoline to oil. The higher the number (i.e. 50:1 vs 40:1) means there is a higher concentration of gas in the mixture than oil. The key here is that we are dealing with a bottle of oil measuring 6.4 ounces. A gallon of gas measures 128 ounces. If we mix this bottle with 2 gallons of gas, the ratio of gas to oil will be 40:1 (2 gallons gas = 128 oz/gal x 2 gals =256 ounces --> 256 ounces divided by 6.4 ounces = 40. Therefore, mixing the 6.4 oz bottle of oil with 2 gallons of gas results in a 40:1 mixture). If the contents of this bottle are mixed with 2.5 gallons gas, the resulting mixture is 50:1 (2.5 gallons = 128 oz/gal x 2.5 gals = 320 ounces. 320 ounces divided by 6.4 ounces = 50, resulting in the 50:1 mixture that is labeled on the bottle pictured). The easiest way to get the proper mixture is to determine what mixture your equipment requires, then buy the proper amount of gas to mix with the oil. In summary, for a 50:1 mixture, pour the entire contents of the 6.4 oz oil bottle in 2.5 gallons of gas; for a 40:1 mixture, pour the 6.4 oz bottle into 2 gallons of gas.
No, you need 3.2oz of this 50:1 oil added to one gallon of E10 gas to to make one gallon of 40:1 mix.
Yes It will be fine for any engine provided you follow the Mfg. specified mix ratio.
No all of your question is being displayed. A 16 to 1 ratio of gas to oil and you have 1 gallon of gas and mixing in 8 oz of oil would be correct. Hope that was the answer you were asking for.
As long as the oil needs to be mixed in with the gas then it should work fine. Works on all 2 cycle engines.